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Asked: 2024-09-27T10:43:10+05:30 In:

How can I find the position of two adjacent uppercase letters in a string using Python? I’m looking for an efficient way to accomplish this task, specifically to retrieve the index of where this pattern occurs. Any suggestions or code examples would be appreciated!

I’ve been playing around with string manipulations in Python, and I stumbled upon a quirky problem that I can’t seem to find an elegant solution to. So, I thought I’d reach out to see if anyone’s had any luck with this.

Here’s the situation: I’m trying to locate the position of two adjacent uppercase letters in a string. Yeah, I know it sounds a bit specific, but hear me out! I’ve got this string that contains all sorts of characters, including uppercase letters, lowercase letters, numbers, and special characters. My goal is to efficiently find the index of any occurrence where two uppercase letters appear right next to each other.

For example, in the string “Hello World, THIS is Python!”, I want to identify where “TH” appears (which would be at index 13). It’s a bit of a puzzle because I want to ensure the solution is as efficient as possible, since I plan to run it on some really long strings later on.

I’ve experimented with various approaches—some using loops, others with regular expressions. But I just can’t seem to land on a method that feels right without becoming a performance drag. If I use regular expressions, I know I can search for the pattern fairly quickly, but I’m not sure how to retrieve just the index of the match efficiently.

I’d love to see if anyone has tackled a similar problem and how you went about it. Maybe you have a nice, concise piece of code that does the trick? Or perhaps there’s a clever trick or a library you used that made it feel less daunting? Any insights or code snippets would be super helpful! I’m all ears for creative solutions or even just some tips on optimizing the search.

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    2 Answers

    1. Sounds like a fun little challenge! Finding those two adjacent uppercase letters can indeed be tricky. Since you want a solution that’s efficient, using regular expressions is a pretty good idea. They can help you skip over the string quickly without needing to loop through each character one by one.

      Here’s a simple way to do it using Python’s `re` module:

      import re

# Your example string
text = "Hello World, THIS is Python!"

# Regular expression pattern to find two adjacent uppercase letters
pattern = r'([A-Z]{2})'

# Use re.search to find the first occurrence
match = re.search(pattern, text)

if match:
    index = match.start()  # Get the starting index of the match
    print(f'The index of the first occurrence of adjacent uppercase letters is: {index}')
else:
    print('No adjacent uppercase letters found.')

      This code will search for the pattern of two uppercase letters and return their starting index. The `re.search()` function is efficient because it stops searching once it finds the first match. If you want to find all matches instead of just the first, you could use `re.finditer()` which returns an iterator yielding match objects. Here’s how you could do that:

      matches = re.finditer(pattern, text)

for match in matches:
    print(f'Found "{match.group()}" at index {match.start()}')

      With this, you’ll get the index for every occurrence of two adjacent uppercase letters! Give it a try on your string and see how it performs. Happy coding!

    2. To tackle the problem of finding the index of two adjacent uppercase letters in a string, a straightforward and efficient approach involves using regular expressions, which are both powerful and concise for pattern matching tasks. You can utilize the `re` module in Python, specifically the `re.search()` function to look for the pattern of two uppercase letters in your string. The regular expression pattern `r'[A-Z]{2}’` effectively captures this requirement. In tandem with the `start()` method of the match object, you can easily retrieve the index of the first occurrence. Here’s a sample code snippet that illustrates this approach:

      import re

def find_adjacent_uppercase(s):
    match = re.search(r'[A-Z]{2}', s)
    return match.start() if match else None

test_string = "Hello World, THIS is Python!"
index = find_adjacent_uppercase(test_string)
print(index)  # Output: 13

      This approach is efficient as it leverages the power of regular expressions, which are optimized for string searching tasks, thus ensuring that even with long strings, the function performs well. If you’re considering performance alone, using regular expressions is typically better than looping through the string manually, especially for longer inputs where execution time can significantly increase. This solution should make your string manipulation both simpler and more efficient, allowing you to focus on other aspects of your project.

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