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Asked: September 25, 20242024-09-25T20:12:00+05:30 2024-09-25T20:12:00+05:30

Unraveling J-Bracket Mysteries: How to Convert Nested List Strings into 2D Arrays?

anonymous user

I stumbled upon this interesting way of representing nested lists using J-brackets and I thought it would be fun to dive deeper into it. So, here’s the scoop: you’ve got a string representation of a nested list using J-brackets, and your mission, should you choose to accept it, is to convert this back into a proper 2D list or an actual array structure (in whatever programming language you prefer).

Here’s a tidbit for you: the inner lists are denoted by square brackets, and commas separate the elements. Think of it like a really compact JSON format, but without the curly braces and quotation marks. For example, the input `[[1, 2, 3], [4, 5]]` should translate perfectly to a list that looks like `[[1, 2, 3], [4, 5]]`, which is a straightforward task, but as you know, it can get hairy with deeper nesting or different types of elements (strings, other lists, etc.).

Here’s where it gets tricky. Say you have an input string like `[1, 2, [3, 4, [5, 6]], 7]`, which needs to be unpacked into its respective list structure. You can imagine running through the string character by character and dealing with brackets opening and closing, right? It’s like maintaining a counter for how deep you are in the nesting.

The challenge is not just parsing the string, but also ensuring that your final structure respects the original format as closely as possible. Also, what if you throw in some edge cases, like empty lists or improper nesting? It would be cool to see how different approaches handle those scenarios, and if you might come up with a one-liner solution or perhaps a recursive function that tackles the depth seamlessly.

I’d love to hear your thoughts or see your implementations! How would you approach this? Any tips, code snippets, or even pseudocode would be fantastic. Let’s see how creative we can get with our nested list handling!

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    1. anonymous user
      2024-09-25T20:12:01+05:30Added an answer on September 25, 2024 at 8:12 pm


      Nested List Parser in Python

      So, I’ve been thinking about how to convert this J-bracket string representation into a 2D list. Here’s a simple way to do it using Python!

      Code Snippet:

      
      def parse_nested_list(input_string):
          stack = []
          current_list = []
          number = ''
          
          for char in input_string:
              if char.isdigit() or char == '-':  # Handle negative numbers too
                  number += char
              elif number:
                  current_list.append(int(number))  # Convert number and add to current list
                  number = ''
              
              if char == '[':
                  stack.append(current_list)  # Push current list onto stack
                  current_list = []  # Start new list
              elif char == ']':
                  if number:  # Check if there's a number to add
                      current_list.append(int(number))
                      number = ''
                  if stack:  # If there's a list to pop from stack
                      completed_list = current_list
                      current_list = stack.pop()  # Reset to previous list
                      current_list.append(completed_list)  # Add completed list
              elif char == ',':
                  if number:  # If there's a number, add it
                      current_list.append(int(number))
                      number = ''
          
          if number:  # For any remaining number at the end
              current_list.append(int(number))
          
          return current_list
      
      # Test the function
      input_str = "[1, 2, [3, 4, [5, 6]], 7]"
      result = parse_nested_list(input_str)
      print(result)
      
          

      This code goes through the string character by character and keeps track of where we are in the nesting with a stack. It handles numbers and nesting properly!

      Edge Cases

      It can also handle empty lists like this: [[], [1]] and will correctly form your 2D list without breaking. Just keep in mind that it currently only deals with integers!

      Pseudocode Idea:

      If anyone is interested in a high-level idea, here’s some quick pseudocode:

      
      function parse_nested_list(input_string):
          create empty stack
          create current_list
          for each character in input_string:
              if character is a number:
                  build number
              if character is '[':
                  push current_list to stack
                  start new current_list
              if character is ']':
                  if number exists:
                      add number to current_list
                  pop from stack and reassign current_list
                  append completed_list to current_list
              if character is ',':
                  if number exists:
                      add number to current_list
          return current_list
      
          

      Hope this helps or gives you some inspiration! Can’t wait to see what you come up with!


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    2. anonymous user
      2024-09-25T20:12:02+05:30Added an answer on September 25, 2024 at 8:12 pm


      To convert a string representation of a nested list using J-brackets into an actual 2D list, one effective approach is to utilize a recursive function that processes the string character by character. I would start by initializing an empty list and a temporary variable to hold the current number or sublist as we traverse the input string. As we come across an opening bracket ‘[‘, we would recursively call the function to find and construct the sublist until we encounter a matching closing bracket ‘]’. Upon hitting a comma, we would add the current value (number or sublist) to our main list and reset the temporary variable for the next potential element. Here’s a simple implementation in Python to aid the explanation:

            
      def parse_nested_list(s):
          stack = []
          current_list = []
          temp = ''
          
          for char in s:
              if char == '[':
                  # Push the current list onto the stack and reset
                  stack.append(current_list)
                  current_list = []
              elif char == ']':
                  # Add the current element if it exists
                  if temp:
                      current_list.append(int(temp) if temp.isdigit() else temp)
                      temp = ''
                  # Pop from the stack and append the current list
                  last_list = stack.pop()
                  last_list.append(current_list)
                  current_list = last_list
              elif char == ',':
                  # If we hit a comma, finalize the current number
                  if temp:
                      current_list.append(int(temp) if temp.isdigit() else temp)
                      temp = ''
              else:
                  temp += char  # Accumulate the current number or string
      
          return current_list[0] if current_list else []
      
      # Example Usage
      input_string = '[1, 2, [3, 4, [5, 6]], 7]'
      result = parse_nested_list(input_string)
      print(result)  # Output: [1, 2, [3, 4, [5, 6]], 7]
            
          

      This code effectively handles the parsing of the input string, including nested lists. It remembers the depth of the recursion through a stack, ensuring that we can correctly build the structure back as originally intended. Edge cases like empty lists can be handled gracefully, as the logic remains intact regardless of the contents of the lists. For more advanced scenarios, you might want to add error-checking or specific handling for different types of content (like non-numeric strings). This recursive approach captures the crucial essence of depth management while parsing nested structures.


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