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Asked: 2025-04-12T22:14:01+05:30

Create bespoke numbers based on specific rules and criteria for code golf challenge.

I’ve been diving into this whole code golf challenge thing lately, and I thought it would be fun to come up with a little problem for all of you to tackle. So, here it goes!

Imagine you need to generate a series of bespoke numbers based on some quirky rules, and your goal is to do it in the fewest number of characters possible—classic code golf style!

Here are the rules you need to follow:

1. You must generate numbers from 1 to n (where n is a positive integer input).
2. For multiples of 3, print “Fizz” instead of the number.
3. For multiples of 5, print “Buzz” instead of the number.
4. For numbers that are multiples of both 3 and 5, print “FizzBuzz”.
5. If a number contains the digit ‘7’, you need to replace it with “Woah!” regardless of other rules.
6. Finally, if the number is a prime number, it’s a chance for a bonus! Instead of that whole output, just print “Prime!”

Oh, and since this is a compact code challenge, keep your code as short as possible. I want to see some creative approaches—use any language you’re comfortable with, but make sure to pay attention to those character counts!

To spice things up, let’s say your function signature should look something like `generateNumbers(n)`, where `n` is the cutoff number you’ll calculate up to. Also, cut off any output that goes beyond the first n elements you should return.

Are you up for the challenge? Can you think of a solution that balances brevity while following all these slightly chaotic rules? I can’t wait to see the clever tricks you guys come up with! And hey, if someone can figure out how to combine those rules in an elegant one-liner, they’re my hero! Let’s see those solutions!

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    2 Answers

    1. Hey, cool challenge! 😅 I’m pretty new at this whole coding-golf thing, but it seemed like a fun puzzle. Here’s my attempt in Python! I tried keeping it short, but man, these rules made it a wild ride. 😵‍💫 (Note: probably not winning any awards for brevity here!) Maybe someone can improve upon it:

      def generateNumbers(n):
 def p(x):return x>1and all(x%i for i in range(2,x))
 return["Woah!"if'7'in str(i)else"Prime!"if p(i)else"FizzBuzz"if i%15==0else"Fizz"if i%3==0else"Buzz"if i%5==0else str(i)for i in range(1,n+1)]

      Man, figuring out prime checking turned out tricky—I definitely wasted some chars there! 😂 Also, figuring out which rule overrides what gave me a minor headache—”Prime!” beats Fizz or Buzz, apparently? Hope I got that right!

      I’m super curious though—surely there’s some wizard programmer here who can squeeze this down waaay shorter? One-liner magic anyone? 🔮 Let me know your tricks—I’d love some pointers!

    2. In addressing the code golf challenge to generate a series of bespoke numbers following the provided quirky rules, a concise function can be implemented using Python. The function `generateNumbers(n)` leverages a loop from 1 to n, checking each number for the various conditions outlined. The rules are prioritized such that if a number is prime, it prints “Prime!” and skips the subsequent checks; if it contains the digit ‘7’, it outputs “Woah!”. For multiples of 3 and 5, it uses conditional statements to print “Fizz”, “Buzz”, or “FizzBuzz” as applicable. Using list comprehension allows for compactness in constructing the final output, combining these conditions efficiently within a minimal character count.

      Here’s a streamlined version of the code that adheres to the challenge’s brevity requirement:

      def generateNumbers(n):
    for i in range(1, n + 1):
        primes = all(i % j for j in range(2, int(i ** 0.5) + 1)) if i > 1 else False
        out = "Prime!" if primes else "Woah!" if '7' in str(i) else "FizzBuzz" * (i % 15 == 0) or "Fizz" * (i % 3 == 0) or "Buzz" * (i % 5 == 0) or str(i)
        print(out)