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Asked: 2024-09-25T22:12:42+05:30

How can you creatively implement the “FizzFizzFizzBuzz” coding challenge, where multiples of 3 output “Fizz” three times, multiples of 5 output “Buzz,” and multiples of both produce “FizzFizzFizzBuzz,” for numbers 1 to 100?

I’ve been playing around with some fun coding challenges lately, and one that really caught my interest is a twist on the classic FizzBuzz problem. If you’re familiar with FizzBuzz, you usually count up to a certain number, replacing multiples of 3 with “Fizz,” multiples of 5 with “Buzz,” and multiples of both with “FizzBuzz.” Pretty straightforward, right?

Well, this version adds an interesting twist called “FizzFizzFizzBuzz.” The basic premise remains the same, but we need to adapt our approach a little bit. Here’s the scoop: Instead of just straightforward counting, you have designated output conditions for multiples of 3 and 5, but the outputs change with some specific numbers.

Here’s the catch: when you encounter a multiple of 3, you should output “Fizz” three times (so “FizzFizzFizz”). For multiples of 5, it’s the classic “Buzz.” However, for numbers that are multiples of both 3 and 5—you guessed it—it’s “FizzFizzFizzBuzz.”

I’m curious about how would you go about coding this? I think it’s more challenging and creative than the usual FizzBuzz because you have to account for those extra Fizz outputs. I’ve tossed around a few ideas in my head, but I’m still trying to nail down a clean and efficient solution.

To set up the challenge, let’s say we want to extend this to 100 numbers. So, your output should be a string with each output separated by a space, counting from 1 to 100. I’m sure there are plenty of elegant solutions out there, possibly using different programming languages or paradigms.

Would love to see what you all come up with! If you’re interested, think about your coding style and the approach you take—would love to hear the reasoning behind your solutions and maybe even see some code snippets! And honestly, if your code does something quirky, like adds a funny comment or a meme reference, that would make it even better. Let’s see who can tackle FizzFizzFizzBuzz in the most unique way!

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    2 Answers



    1. FizzFizzFizzBuzz Challenge

      FizzFizzFizzBuzz Challenge!

      This looks like a fun twist on FizzBuzz! Here’s how I’d tackle it in JavaScript:

              
            // FizzFizzFizzBuzz Function
            function fizzFizzFizzBuzz() {
                let result = [];
                for (let i = 1; i <= 100; i++) {
                    if (i % 3 === 0 && i % 5 === 0) {
                        result.push("FizzFizzFizzBuzz");
                    } else if (i % 3 === 0) {
                        result.push("FizzFizzFizz");
                    } else if (i % 5 === 0) {
                        result.push("Buzz");
                    } else {
                        result.push(i);
                    }
                }
                return result.join(" ");
            }

            // Output the result
            console.log(fizzFizzFizzBuzz());

      So, basically, I just loop from 1 to 100 and check each number. If it's both 3 and 5, I add "FizzFizzFizzBuzz" to my result. If it's only 3, I add "FizzFizzFizz." For 5, just "Buzz." If it’s none of those, I just put the number itself. Super simple, right? 😄

      Can't wait to see other versions!


    2. “`html

      The FizzFizzFizzBuzz challenge presents a fun twist to the classic coding problem by adding an additional layer of complexity. To tackle this problem effectively, we can use a simple loop structure to iterate through the numbers from 1 to 100 and apply conditional logic to determine the correct output for each number. The core logic involves using the modulus operator (%) to check for multiples of 3 and 5. When we encounter a multiple of 3, we will append “FizzFizzFizz” to our output string, while for multiples of 5, we will append “Buzz.” Finally, for numbers that are multiples of both 3 and 5, we will append “FizzFizzFizzBuzz” to our output string.

      Here’s a concise implementation in Python that demonstrates this approach:

      
def fizz_fizz_fizz_buzz(n):
    output = []
    for i in range(1, n + 1):
        if i % 3 == 0 and i % 5 == 0:
            output.append("FizzFizzFizzBuzz")
        elif i % 3 == 0:
            output.append("FizzFizzFizz")
        elif i % 5 == 0:
            output.append("Buzz")
        else:
            output.append(str(i))
    return ' '.join(output)

print(fizz_fizz_fizz_buzz(100))

      “`

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