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Asked: 2024-09-26T18:26:43+05:30 In:

How to Calculate 3BV Metric for a Minesweeper Board in Python?

I’ve been playing Minesweeper a lot lately, and I stumbled upon something kind of interesting that I want to dive into. So, I was wondering if anyone could help me tackle this problem related to calculating the 3BV (Boulder, Bomb, and Victory) metric of a Minesweeper board.

Here’s the thing: in Minesweeper, each square can either be a bomb or a number indicating how many bombs are adjacent to that square. The 3BV metric is a way to quantify the complexity of a Minesweeper board, and I think it would be fun to explore how to calculate it.

To break it down a bit, we consider three key components:

1. **Boulders:** These are the safe squares that you can click on which don’t have any adjacent bombs. For 3BV, you count how many such squares there are.

2. **Bombs:** Well, this is straightforward—every mine you place on the board contributes directly to the 3BV. So, you simply count the total number of bombs on the board.

3. **Victory Squares:** These squares refer to the safe squares that you need to reveal in order to win the game. It includes all the safe squares you can uncover based on the game rules.

Now, my question is: how can I create a function or a method that takes a Minesweeper board (represented as a 2D grid) as input and correctly calculates the 3BV based on these three criteria? If you could share some code snippets or even just the logic behind your approach, that would be amazing!

Also, if you could mention any edge cases to watch out for (like what happens when the board is completely empty or entirely filled with bombs), that would be super helpful too. I want to make sure I cover all bases here!

Looking forward to seeing your ideas and solutions!

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    2 Answers

    1. Calculating the 3BV Metric for a Minesweeper Board

      To calculate the 3BV (Boulder, Bomb, and Victory) metric for a Minesweeper board represented as a 2D grid, you can follow the steps below.

      Steps to Calculate 3BV

      1. Count Boulders: Look for all squares that don’t have any adjacent bombs.
      2. Count Bombs: Simply count the cells that contain bombs.
      3. Count Victory Squares: Identify safe squares that can be revealed based on the game rules.

      Sample Code in JavaScript

          
      function calculate3BV(board) {
        let boulders = 0;
        let bombs = 0;
        let victorySquares = 0;

        const rows = board.length;
        const cols = board[0].length;

        for (let r = 0; r < rows; r++) {
          for (let c = 0; c < cols; c++) {
            if (board[r][c] === 'B') { // 'B' for Bombs
              bombs++;
            } else if (board[r][c] === '0') { // '0' for Boulders
              boulders++;
            } else if (board[r][c] !== ' ') { // Any numbered square
              victorySquares++;
            }
          }
        }

        return boulders + bombs + victorySquares;
      }

      // Example of a Minesweeper board
      const board = [
        [' ', '1', 'B', '1'],
        ['0', '1', '1', '0'],
        ['B', '0', '0', ' '],
        [' ', 'B', ' ', ' ']
      ];

      console.log(calculate3BV(board));

      Edge Cases to Consider

      • If the board is empty (no squares), the 3BV should be 0.
      • If the board is entirely filled with bombs, the 3BV will equal the number of bombs.
      • If all squares are boulders, the 3BV will equal the number of boulders.

      This should give you a good starting point for working with the 3BV metric! Happy coding!

    2. To calculate the 3BV (Boulder, Bomb, and Victory) metric for a Minesweeper board represented as a 2D grid, we can define a function in Python that iterates through the grid and counts the three components: boulders, bombs, and victory squares. Below is a sample implementation of the function:

      def calculate_3bv(board):
    boulders = 0
    bombs = 0
    victory_squares = 0
    
    rows = len(board)
    cols = len(board[0]) if rows > 0 else 0

    for i in range(rows):
        for j in range(cols):
            if board[i][j] == -1:  # Assuming -1 represents a bomb
                bombs += 1
            elif board[i][j] == 0:  # Assuming 0 represents a boulder
                boulders += 1
                # Check for victory squares by revealing adjacent squares
                victory_squares += reveal_victory_squares(board, i, j)

    total_3bv = boulders + bombs + victory_squares
    return total_3bv

def reveal_victory_squares(board, x, y):
    # Placeholder function for revealing victory squares logic
    # Implement logic to count additional victory squares if needed
    return 1  # Simplified assumption that each boulder can be a victory square

      In this code, we scan the board for bombs and boulders, counting them directly. The function reveal_victory_squares is a placeholder where you can implement logic to determine specific victory squares based on your game’s rules. Edge cases to consider include boards entirely filled with bombs (where the count of bombs would be equal to the grid size) and completely empty boards (where both boulders and bombs would be zero). Make sure to adjust the bomb and boulder definitions based on how you represent them in your grid (e.g., using -1 for bombs, 0 for boulders, and positive numbers for numbered squares indicating bomb proximity).

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