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Asked: 2024-09-27T09:06:21+05:30

How to Implement FizzBuzz with Fibonacci Numbers in Your Coding Challenge?

I stumbled upon this really cool coding challenge the other day, and it got me thinking—what a fun way to play with numbers! The challenge mixes Fibonacci numbers with the classic FizzBuzz game, and I wanted to share it to see how others would tackle it.

So, here’s the scoop: you’re supposed to generate a sequence using Fibonacci numbers but with a twist. Instead of printing just the Fibonacci numbers, you need to replace certain numbers with “Fizz,” “Buzz,” or “FizzBuzz.” The rules are pretty similar to FizzBuzz—here’s how it goes:

1. You start with the traditional Fibonacci sequence: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, and so on.
2. For every Fibonacci number that is divisible by 3, you should print “Fizz.”
3. For every Fibonacci number that is divisible by 5, you should print “Buzz.”
4. And for numbers that are divisible by both 3 and 5, you print “FizzBuzz.”
5. If a Fibonacci number isn’t divisible by either, just print the number itself.

For example, the beginning of the sequence would look like this:
– 0 (Fizz)
– 1 (just 1)
– 1 (just 1)
– 2 (just 2)
– 3 (Fizz)
– 5 (Buzz)
– 8 (just 8)
– 13 (just 13)
– 21 (Fizz)
– 34 (just 34)

It’s a neat way to combine math and conditional logic, and it prompted me to think about how efficient one could be while implementing this. If you were given a limit, say the first 20 Fibonacci numbers, how would you go about writing this? What language would you choose, and what kind of clever tricks would you use to keep your code concise but readable?

I’m really curious to see the different approaches you all might come up with! Are there any optimizations you’d make? Do you have a favorite way to handle the divisibility checks? The floor is yours—let’s see who has the best solution!

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    2 Answers

    1. 
def fibonacci_fizzbuzz(n):
    fib = [0, 1]
    result = []
    
    # Generate Fibonacci sequence
    for i in range(2, n):
        next_fib = fib[i - 1] + fib[i - 2]
        fib.append(next_fib)
    
    # Check conditions for Fizz, Buzz, and FizzBuzz
    for number in fib:
        if number % 3 == 0 and number % 5 == 0:
            result.append("FizzBuzz")
        elif number % 3 == 0:
            result.append("Fizz")
        elif number % 5 == 0:
            result.append("Buzz")
        else:
            result.append(str(number))
    
    return result

# Get first 20 Fibonacci numbers FizzBuzz
fizzbuzz_sequence = fibonacci_fizzbuzz(20)
print(fizzbuzz_sequence)

    2. This coding challenge is a fantastic way to blend mathematical concepts with programming logic! To tackle this, we can write a Python program that generates the Fibonacci sequence up to the 20th number while adhering to the FizzBuzz rules. By using a simple loop and conditional statements, we can efficiently check the conditions for each Fibonacci number. Here’s a straightforward implementation:

      
def fibonacci_fizzbuzz(limit):
    fib_seq = [0, 1]
    while len(fib_seq) < limit:
        fib_seq.append(fib_seq[-1] + fib_seq[-2])
    
    for num in fib_seq:
        if num % 3 == 0 and num % 5 == 0:
            print("FizzBuzz")
        elif num % 3 == 0:
            print("Fizz")
        elif num % 5 == 0:
            print("Buzz")
        else:
            print(num)

fibonacci_fizzbuzz(20)

      In this implementation, we first generate the Fibonacci sequence by repeatedly adding the last two numbers until we reach the desired limit of 20 numbers. The divisibility checks for 3 and 5 are then handled using a series of `if-elif-else` statements. This code maintains readability while efficiently achieving the desired output. Additionally, you could optimize by avoiding the storage of the entire Fibonacci sequence in memory if needed, by calculating the next number directly in the loop. This would be a great exercise in both mathematical thinking and coding skill!

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