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Asked: 2024-09-25T17:47:49+05:30 In:

Quirky Function Design: How to Return 3 from Specific Inputs in JavaScript?

anonymous user

I stumbled upon this interesting coding challenge the other day, and I thought it might be fun to get your thoughts on it! The challenge involves creating a JavaScript function that behaves a bit differently based on how it receives its input. The idea is that the function should return the number 3 for two specific inputs: when you pass it the individual numbers 1 and 2 (so basically, `add(1, 2)` should return 3) as well as when you pass a single number 12 (so `add(12)` should also return 3).

The catch, though, is how you implement it. It sounds simple enough, but I found myself scratching my head a little. If you’re like me and enjoy these kinds of quirky coding challenges, I’m curious to hear how you’d approach this! What kind of tricks or techniques would you use to get the function to differentiate between the two scenarios?

For an added twist, I’m wondering how you could make your function as compact as possible. You know, the kind of challenge where solving it with a few clever lines of code feels really satisfying? I’m sure there are numerous ways to achieve this, and I’d love to see your solutions!

Oh, and here’s another thought—what if we expand the challenge? Could you think of any additional inputs that would break the initial rules? For example, what might happen if someone inputs a string or an array? How would you handle those cases, or would you choose to ignore them?

I can’t wait to see the creative solutions you all come up with. This challenge really gets you thinking about function design and edge cases. Sharing your code snippets and thought process would be super interesting, too! Happy coding!

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    2 Answers

    1. anonymous user


      function add(...args) {
    if (args.length === 1 && args[0] === 12) {
        return 3; // Single input case
    } else if (args.length === 2 && args[0] === 1 && args[1] === 2) {
        return 3; // Two input case
    }
    return null; // Handle other cases
}

// Test cases
console.log(add(1, 2)); // Should print 3
console.log(add(12));   // Should print 3
console.log(add(5));    // Should print null
console.log(add(1, 3)); // Should print null
console.log(add("12")); // Should print null
console.log(add(1, 2, 3)); // Should print null
console.log(add([1, 2])); // Should print null

      To handle additional inputs like strings or arrays, you could simply check the type using `typeof` or `Array.isArray`.

      function add(...args) {
    if (args.length === 1 && args[0] === 12) {
        return 3; 
    } else if (args.length === 2 && args[0] === 1 && args[1] === 2) {
        return 3; 
    } else if (typeof args[0] === 'string' || Array.isArray(args[0])) {
        return null; // Ignore strings and arrays
    }
    return null; // Handle other cases
}


    2. anonymous user


      To tackle the coding challenge of creating a JavaScript function that returns 3 for specific inputs, we can utilize a conditional structure to differentiate between the scenarios. The function will check the number and the number of arguments it receives. Here’s a concise solution that accomplishes this:

      function add(...args) {
    return (args.length === 2 && args[0] === 1 && args[1] === 2) || (args.length === 1 && args[0] === 12) ? 3 : null;
}

      This function takes a variable number of arguments using the spread operator (`…args`). It checks if the arguments match either of the required patterns: two arguments of 1 and 2, or a single argument of 12. If the criteria are met, it returns 3; otherwise, it returns null. As for edge cases such as strings or arrays, we can enhance the function to ignore invalid inputs by adding a check for the types of the arguments. This will ensure that the function behaves predictably while not processing unexpected data types. Here’s how we can refine it:

      function add(...args) {
    if (args.every(arg => typeof arg === 'number')) {
        return (args.length === 2 && args[0] === 1 && args[1] === 2) || (args.length === 1 && args[0] === 12) ? 3 : null;
    }
    return null;
}


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