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Asked: May 4, 20252025-05-04T22:14:46+05:30 2025-05-04T22:14:46+05:30

Create a function to count block-covered cycles in a grid with specific conditions.

anonymous user

Imagine you’re diving into the fascinating world of grids and cycles, and I have a fun yet challenging problem that I think you’ll enjoy! Picture a grid made up of blocks – think of it as a classic checkerboard pattern. Now, these blocks can either be occupied or free, and you need to identify cycles formed by a sequence of occupied blocks.

Here’s the catch: a cycle is defined as a sequence of occupied blocks that form a closed loop, meaning you can start at one block, follow the blocks that connect (up, down, left, or right), and return to your starting point without retracing your steps. Additionally, to keep things interesting, let’s say each cycle must contain at least three blocks and cannot share blocks with any other cycles.

So, how would you approach creating a function to count these block-covered cycles in a given grid? It sounds simple enough, but there’s a twist – cycles can vary in shape and size, making it a bit tricky to implement your logic. Plus, since grids can be pretty large, you’ll need your function to be efficient to ensure it runs in a reasonable time even for larger dimensions.

To get you started, consider how you would represent this grid. Would you use a 2D array? What conditions would you check when traversing the blocks to determine if they are part of a cycle? And how would you ensure that cycles are counted only once, and not double-counted?

Now, I’m really curious to hear your thoughts. How would you structure your function? What algorithms or strategies would you consider to effectively navigate through the grid and count those cycles? Let’s put our thinking caps on and crack this grid challenge together! I can’t wait to see your approaches and solutions.

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    1. anonymous user
      2025-05-04T22:14:48+05:30Added an answer on May 4, 2025 at 10:14 pm

      To tackle the problem of counting cycles in a grid of occupied blocks, my approach would begin with representing the grid as a 2D array, where each cell indicates whether it’s occupied or free. To identify cycles, a depth-first search (DFS) algorithm would be a fitting choice. This method enables us to traverse the grid while keeping track of visited blocks. During the traversal, I would consider each occupied block and explore its neighboring blocks (up, down, left, right). A stack or recursion could be employed to help backtrack upon reaching a dead end. We must also ensure that once a cycle is detected, the blocks involved are marked as visited to prevent double-counting.

      In addition to the above, I would implement a mechanism to confirm that a cycle comprises at least three blocks before counting it. As part of the traversal, I would maintain a separate list of blocks that form the current path. If we return to the starting block of our path and confirm its length is three or more, we can consider it a valid cycle. This implementation can be optimized further by leveraging memoization or BFS when traversing larger grids to minimize backtracking redundancies. Overall, achieving efficiency will be crucial, especially as grid size increases, and careful management of the visited state will ensure all cycles are counted accurately without repetition.

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    2. anonymous user
      2025-05-04T22:14:47+05:30Added an answer on May 4, 2025 at 10:14 pm

      Hmm, this sounds kinda tricky, but let’s break it down step-by-step!

      First, I’d say let’s use something simple—like a 2D grid (you know, an array of arrays) to represent this problem. Something like:

      let grid = [
        ['occupied', 'free', 'occupied'],
        ['occupied', 'occupied', 'occupied'],
        ['free', 'occupied', 'free']
      ];
        

      Then, we probably want to loop through every cell and see if it’s occupied. If it is, we start exploring its neighbors (up, down, left, right) to see if we can make a loop back to it. It sounds like maybe we can use some sort of Depth-First Search (DFS) algorithm here?

      Okay, maybe we’ll need a helper function that explores blocks next to our starting spot and remembers which blocks it’s visited already. When exploring, we have to make sure we don’t go backward immediately (avoid backtracking to the previous block we came from). If at some point we return to the first block we started from after going through at least two other blocks (three in total or more), we’ll have found a cycle!

      Not sure if this makes sense, but the structure could be something like:

      1. Loop over each block in the grid.
      2. If block is occupied and not previously visited, start DFS from there.
      3. Doing the DFS, mark the blocks we visit.
      4. While doing DFS, look out for situations where we revisit a block we already saw—if that block is not the immediate previous block, it means we found a cycle.

      Also, to stop cycles from being counted more than once or from overlapping, anytime we find a cycle, we could mark all its blocks as “visited” and then not revisit those blocks ever again.

      I guess this can lead to faster code because we’re making sure that each cycle is discovered and counted only once, and blocks are not being rechecked again and again.

      I hope this makes sense? Not entirely sure I thought of everything yet, but maybe I’ll try coding up a basic DFS first and test it on a small grid to see if it’s doing what I expect. The tricky bit I’m seeing here is definitely the marking of visited blocks correctly and making sure we only count each cycle once, haha.

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