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Asked: 2024-09-25T23:53:43+05:30

FizzBuzz Prime Twist: A Creative Coding Challenge!

I’ve been playing around with some coding challenges lately, and I came across a super fun one that involves a twist on the classic FizzBuzz! I thought I’d share it and see how creative you all can get with your solutions.

The challenge is simple but has some fun variations. Instead of just counting from 1 to n and replacing multiples of 3 with “Fizz” and multiples of 5 with “Buzz,” we mix it up a bit. The rules are as follows:

1. For every number that is divisible by 3, you replace it with “Fizz.”
2. For every number that is divisible by 5, you replace it with “Buzz.”
3. If a number is divisible by both 3 and 5, you use “FizzBuzz.”
4. But here comes the kicker: if the number is a prime number, you return “Prime!” instead. If it’s a prime number that also happens to be divisible by 3 or 5, the prime takes precedence over the other conditions.

I know, it gets pretty interesting when you start mixing those conditions! For instance, the number 3 should output “Prime!” since it’s a prime, even though normally it would just be “Fizz.” Similarly, the number 5 would also give “Prime!” because, again, it’s a prime.

I would love to see how you tackle this problem, especially considering your approach to finding prime numbers efficiently within the sequence. Do you go for a traditional method or use some nifty tricks? What language are you using, and how do you structure your code to keep it neat and readable?

Lastly, I’d really appreciate it if we could have a bit of fun with this. Share not just your final solution, but any interesting logic or thought process you went through while solving this. Can’t wait to see what everyone comes up with!

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    2 Answers



    1. FizzBuzz Prime Challenge

      FizzBuzz with Primes!

      Here’s my take on the FizzBuzz challenge with the prime twist!

              
function isPrime(num) {
    if (num <= 1) return false; // 1 and below are not prime
    for (let i = 2; i <= Math.sqrt(num); i++) {
        if (num % i === 0) return false; // Found a divisor, not prime
    }
    return true; // No divisors found, it's prime
}

function fizzBuzzPrime(n) {
    for (let i = 1; i <= n; i++) {
        if (isPrime(i)) {
            console.log("Prime!");
        } else if (i % 3 === 0 && i % 5 === 0) {
            console.log("FizzBuzz");
        } else if (i % 3 === 0) {
            console.log("Fizz");
        } else if (i % 5 === 0) {
            console.log("Buzz");
        } else {
            console.log(i);
        }
    }
}

// You can call the function like this:
fizzBuzzPrime(30);

      So, here I use the isPrime function to check if a number is prime. Then in my fizzBuzzPrime function, I loop through all numbers from 1 to n. If a number is prime, it gets "Prime!" printed. If it's not prime, I check for Fizz, Buzz, or FizzBuzz. Super fun!

      I'm still learning about efficiency, but using Math.sqrt(num) in my loop to check prime status is a cool trick I found! Can't wait to see what others come up with!




    2. Enhanced FizzBuzz Challenge

      Enhanced FizzBuzz with Prime Check

      The enhanced FizzBuzz challenge adds an exciting twist by incorporating prime number checks into the traditional logic. Below is an implementation in Python, where we’ve defined a function to check for primality and integrated this into the FizzBuzz computation. The function `is_prime` efficiently checks for prime numbers, while the `fizzbuzz_prime` function iterates through a specified range. It checks each number against the defined rules while prioritizing the prime condition when applicable. 

      def is_prime(num):
    if num <= 1:
        return False
    for i in range(2, int(num**0.5) + 1):
        if num % i == 0:
            return False
    return True

def fizzbuzz_prime(n):
    for i in range(1, n + 1):
        if is_prime(i):
            print("Prime!")
        elif i % 3 == 0 and i % 5 == 0:
            print("FizzBuzz")
        elif i % 3 == 0:
            print("Fizz")
        elif i % 5 == 0:
            print("Buzz")
        else:
            print(i)

# Example usage
fizzbuzz_prime(30)

      This implementation emphasizes clarity and efficiency. The `is_prime` function reduces unnecessary checks by only iterating up to the square root of the number. The main loop in `fizzbuzz_prime` uses conditional statements to assess each number, ensuring that the prime condition takes precedence over the Fizz and Buzz conditions. Such a structured approach not only keeps the code neat but also makes the logic easy to follow. I encourage everyone to experiment with the upper limit and possibly optimize the prime check further if tackling larger numbers!


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