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Asked: 2024-09-22T22:58:17+05:30 In:

How can I pass a dictionary to a function in Python so that the keys are treated as keyword arguments? What is the correct syntax to achieve this?

Hey everyone!

I’m working on a Python project where I need to pass a dictionary to a function. I want the dictionary keys to be treated as keyword arguments. I know there’s a way to do this using the `**` operator, but I’m not entirely sure about the correct syntax to make it work.

Can someone explain how I can achieve this? Maybe share a quick example? I’d really appreciate your help! Thanks!

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    2 Answers



    1. Python Dictionary as Keyword Arguments

      Using a Dictionary as Keyword Arguments in Python

      Hi there! No worries, it’s great that you’re getting into Python!

      To pass a dictionary to a function and use its keys as keyword arguments, you can use the ** operator. Here’s how it works:

      def my_function(name, age, city):
    print(f'Name: {name}, Age: {age}, City: {city}')

my_dict = {'name': 'Alice', 'age': 30, 'city': 'New York'}

my_function(**my_dict)

      In this example:

      • We defined a function called my_function that takes three parameters: name, age, and city.
      • We created a dictionary called my_dict with keys that match the function parameters.
      • Finally, we called the function using **my_dict. This unpacks the dictionary and passes its keys and values as keyword arguments.

      When you run this code, you should see the following output:

      Name: Alice, Age: 30, City: New York

      Hope this helps! Happy coding!



    2. To pass a dictionary to a function as keyword arguments in Python, you can utilize the `**` operator, which unpacks the dictionary. The function you want to call should have parameters that align with the keys of the dictionary. For instance, consider the following function definition:

      def print_info(name, age, city):
    print(f'Name: {name}, Age: {age}, City: {city}')

      Now, if you have a dictionary with the corresponding keys:

      info_dict = {'name': 'Alice', 'age': 30, 'city': 'New York'}

      You can call the function by unpacking the dictionary using the `**` operator:

      print_info(**info_dict)

      This will output: Name: Alice, Age: 30, City: New York.


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