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Asked: 2024-09-26T16:33:10+05:30

How to Implement a Base-Dependent FizzBuzz Challenge in Any Programming Language?

I’ve got a fun little challenge for anyone who enjoys playing around with numbers and coding! You know the classic FizzBuzz problem, right? The one where you print numbers from 1 to n, but for multiples of 3 you output “Fizz,” for multiples of 5 you output “Buzz,” and for multiples of both, you output “FizzBuzz”? Well, I thought, why not spice things up a bit by adding bases into the mix?

Here’s the twist: instead of just working in base 10, what if we could do the FizzBuzz challenge in any base? Imagine you’re tasked with writing a FizzBuzz program that accepts two parameters: a base and a range (1 to n). The catch? You have to adjust the Fizz and Buzz conditions based on the representation of numbers in that particular base.

For example, in base 5, the number 15 would actually be represented as 30, and you’d need to figure out when to output “Fizz,” “Buzz,” or “FizzBuzz” depending on the base’s rules and how the numbers are structured in that system. So in base 5, you’d be looking for multiples of 3 (which still counts as Fizz) and multiples of 4 (for Buzz).

Now, here’s the challenge: how would you implement this? What kind of logic and code would you use to ensure your program can take in any base and produce the correct output?

And for those who are really game, let’s make it even more interesting: can you create your function in a compact way, keeping in mind the spirit of code golfing? The fewer characters your solution uses, the better!

I’m really curious to see how creative you all can get with this. Whether you prefer Python, Ruby, JavaScript, or some obscure language, I can’t wait to see your unique takes on this FizzBuzz conundrum. So, who’s in? Show me your solutions and let’s see who can nail this challenge in the most elegant or clever way!

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    2 Answers

    1. Here’s a Python implementation of the enhanced FizzBuzz challenge that takes a base and a range to produce the desired output. The logic checks for multiples of 3 and 4 in the specified base and handles number representation accordingly:

      def fizzbuzz_base(base, n):
    for i in range(1, n + 1):
        fizz = i % 3 == 0
        buzz = i % 4 == 0
        output = "" 
        if fizz: output += "Fizz"
        if buzz: output += "Buzz"
        print(output or i)

# Example usage:
fizzbuzz_base(5, 20)

      This code defines a function `fizzbuzz_base` that takes a `base` and a range limit `n`. Inside the function, it iterates from 1 to n, checking if each number is a multiple of 3 or 4, and constructs the output string accordingly. The output is printed for each number, showing either “Fizz,” “Buzz,” “FizzBuzz,” or the number itself based on the conditions set for the specified base.

    2. 
function fizzBuzzBase(base, n) {
    for (let i = 1; i <= n; i++) {
        let output = '';
        if (i % 3 === 0) output += 'Fizz'; // Check for Fizz (base 10)
        if (i % 4 === 0) output += 'Buzz'; // Check for Buzz (base 10)
        if (output === '') output = i.toString(base); // Convert number to the specified base
        console.log(output);
    }
}

// Example usage: fizzBuzzBase(5, 20);

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