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Asked: 2024-09-25T11:31:21+05:30

Title: Simulating a Left-Center-Right Dice Game: Last Player Standing Challenge

I recently stumbled upon this fun game called Left-Center-Right (LCR), and it got me thinking about how I could automate some of the processes behind it. If you haven’t played it, here’s the gist: Players each have three chips, and on their turn, they roll three dice. Based on the outcome of the dice, they either pass chips to the left, pass chips to the right, or put chips in the center (which is sort of like the bank). The game continues until someone collects all the chips. It sounds simple, but I’m curious about how to implement this in a coding challenge!

So here’s my idea: I want to create a program that simulates a single round of the game for a given number of players. Each player starts with three chips. The program should roll the dice for each player, distribute the chips according to the results, and finally print out how many chips each player has left after their turn. I would love to see how creative people can get with their solutions, especially in terms of keeping the code concise.

To make things interesting, let’s say that if a player loses all their chips, they’re out of the game. So if the round results in a player having no chips left, they should be removed from the game for the remainder of that round. The simulation should terminate when there’s only one player left standing or if all players are eliminated. This could be a great chance for everyone to flex those coding muscles and come up with some neat tricks!

What do you think? Can anyone whip up a solution that’s straightforward yet elegant? If you try your hand at this, I’d love to see different approaches, especially in how you handle the randomness of the dice and player elimination. Also, feel free to suggest any additional features or variations that could spice things up! Looking forward to seeing what you all come up with!

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    2 Answers






    1. Left-Center-Right Game Simulation

      Left-Center-Right Game Simulation

              
            const playersCount = 5; // Number of players
            let players = Array(playersCount).fill(3); // Each player starts with 3 chips

            function rollDice() {
                return Math.floor(Math.random() * 3); // Simulates rolling a die for L, C, R
            }

            function playRound() {
                while (players.filter(chips => chips > 0).length > 1) {
                    for (let i = 0; i < players.length; i++) {
                        if (players[i] > 0) {
                            let rolls = [rollDice(), rollDice(), rollDice()];
                            for (let roll of rolls) {
                                switch (roll) {
                                    case 0: // Pass left
                                        players[i]--;
                                        players[(i + players.length - 1) % players.length]++;
                                        break;
                                    case 1: // Pass right
                                        players[i]--;
                                        players[(i + 1) % players.length]++;
                                        break;
                                    case 2: // Put in center
                                        players[i]--;
                                        break;
                                }
                            }
                        }
                    }
                    console.log(players); // Show how many chips each player has
                }
                console.log("Game over! Chips distribution:", players);
            }

            playRound();

      Feel free to tweak the number of players or add more features!




    2. Left-Center-Right Game Simulation

      Game Simulation Code

              
import random

class Player:
    def __init__(self, name):
        self.name = name
        self.chips = 3

def roll_dice():
    return random.choices(['L', 'C', 'R', None], k=3)

def play_round(players):
    while len(players) > 1:
        for player in players[:]:  # Copying the list to avoid concurrent modification
            if player.chips > 0:
                rolls = roll_dice()
                for roll in rolls:
                    if roll == 'L':
                        player.chips -= 1
                        left_index = (players.index(player) - 1) % len(players)
                        players[left_index].chips += 1
                    elif roll == 'R':
                        player.chips -= 1
                        right_index = (players.index(player) + 1) % len(players)
                        players[right_index].chips += 1
                    elif roll == 'C':
                        player.chips -= 1
                
                if player.chips == 0:
                    print(f"{player.name} is out of the game!")
                    players.remove(player)

    winner = players[0]
    print(f"The winner is {winner.name} with {winner.chips} chips!")

# Simulation example:
players = [Player("Alice"), Player("Bob"), Player("Charlie")]
play_round(players)

      This code defines a simple simulation for a round of Left-Center-Right using Python. Players start with three chips, and the dice rolls determine how chips are distributed. When a player runs out of chips, they are removed from the game, continuing until only one player remains. You can easily extend this program to add more features, such as multiple rounds or different starting chip amounts.


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