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Asked: 2024-09-26T16:02:34+05:30

What are the best coding strategies to count perfect squares below 100 in the least amount of code?

I’ve been playing around with some coding challenges lately and came across something interesting that I wanted to get your thoughts on. The goal is to count all the perfect squares below 100, but I’m curious how you would approach this using the least amount of code possible.

I mean, I’ve seen different methods to tackle this kind of problem, especially when it comes to making the solution as concise as possible. For instance, we could simply loop through all numbers and check if the square root is an integer, but that seems a bit bloated. There’s got to be a more elegant solution, right?

I was thinking, wouldn’t it be cooler if we utilized some mathematical insight? After all, we know that the perfect squares below 100 are \(0, 1, 4, 9, 16, 25, 36, 49, 64, 81, \) and \(100\). That gives us a total of 10 perfect squares if we include 0 but only 9 perfect squares if we stop right before 100.

For coding aficionados, the challenge would be to achieve this in the fewest characters possible. It seems like there are several tricks to reduce code length that I might not even know about. For example, could you leverage some built-in functions in your language of choice to simplify your code? Or maybe use list comprehensions or generator expressions?

I’m also curious to see what languages people prefer for this type of challenge. Some might argue Python’s syntax makes it easier to golf code, while others might prefer JavaScript’s elegance. Or do you think there’s a language that’s even better suited for this sort of task?

So, how would you go about writing the most efficient code to count perfect squares below 100? I’d love to see various approaches and the awesome tricks you come up with to shorten the code. Share your solutions and let’s see who can come up with the most compact and clever code!

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    2 Answers


    1. To count all perfect squares below 100 in a concise manner, a great approach is to leverage the mathematical insight that perfect squares below a given number can be generated by squaring integers starting from 0. Since we know that the largest integer whose square is less than 100 is 9 (because \(9^2 = 81\)), we can simply use a list comprehension in Python to generate these perfect squares efficiently. Here’s a compact solution that accomplishes this:
      perfect_squares = [i**2 for i in range(10) if i**2 < 100]. This one-liner not only generates the list of perfect squares but also ensures that it respects the limit by checking the condition on the squared values.

      In addition, to obtain the count of these perfect squares, we can simply wrap the above in a function and use the built-in len() function to get the total number. Here's the complete code:
      def count_perfect_squares(): return len([i**2 for i in range(10) if i**2 < 100]). When it comes to coding challenges like this, Python often stands out due to its readable syntax and powerful list comprehensions. However, other languages like JavaScript can also achieve similar brevity with features like arrow functions and array methods, making them contenders for “golfing” tasks. Ultimately, the choice of language can depend on personal preference and familiarity with its shorthand syntax.







    2. Perfect Squares Below 100

      Counting Perfect Squares Below 100

      I found a way to count perfect squares under 100 with super short code! Here’s a quick example in Python:


      print(len([x*x for x in range(10)]))

      In this code, range(10) goes from 0 to 9, and x*x gives us the perfect squares. The len function counts them up!

      If you wanna do it in JavaScript, here’s another neat one-liner:


      console.log([...Array(10).keys()].map(x => x*x).length);

      This uses spread syntax and the map function to do the same thing!

      So, super cool, right? Counting perfect squares can be really simple and fun to experiment with! 😊


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