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Asked: 2024-09-25T00:15:57+05:30 In:

You are given a 32-bit signed integer. Your task is to reverse the digits of this integer. However, you need to ensure that the resulting number also remains a 32-bit signed integer. If the reversed integer exceeds this range, you must return 0. For instance, if the input integer is 123, the output should be 321. If the input is -456, the output should be -654. Please take note that leading zeros in the reversed number should be discarded. Implement a function that takes an integer as input and returns the reversed integer as described. Be cautious of overflow scenarios where the reversed integer exceeds the 32-bit signed integer limits.

I’ve got a fun little challenge for you! Imagine you have a 32-bit signed integer, which means its possible values range from -2,147,483,648 to 2,147,483,647. Now, here’s the twist: I want you to reverse the digits of this integer. Sounds simple, right? But wait! You need to be super cautious about the resulting number. If the reversed integer slips outside of that 32-bit signed integer range, your answer should be 0.

Let’s see how this plays out with a few examples. If you get an input like 123, you’d reverse it to get 321. That’s straightforward! But if the input is -456, you reverse it to get -654—easy enough! Just remember, if your answer would normally have leading zeros after you reverse it, you should drop those. For instance, reversing 120 would give you 21, not 021.

Now, the tricky part comes when you find yourself at the edges of the integer limits. Let’s say you input 1,000,000,000. When you reverse that, you get 0000000001, which is just 1, right? No problem there! But imagine if you input a bigger number like 2,147,483,647. When you reverse it, it becomes 7463847412, and that’s beyond the maximum limit. In this case, you would need to return 0 instead.

Here’s a fun exercise: write a function that handles all of these scenarios! You’ll need to check if the reversed integer you get exceeds the 32-bit signed integer limits and deal with leading zeros as well. I’m really curious to see how you would approach this problem. Think about edge cases, overflow issues, and how you’d implement it step by step. Can you come up with a clever solution? I can’t wait to see what you develop! Happy coding!

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    2 Answers



    1. Reverse Integer Challenge

      Reverse Integer Function

      Okay, so I have this problem where I need to flip a number around, but it’s a little tricky because of the whole 32-bit signed integer thing. Like, the numbers can go from -2,147,483,648 to 2,147,483,647, and if I go over that, I have to return 0. That’s kind of scary!

      Here’s what I think I need to do:

      1. I will convert the number to a string so I can reverse it easily.
      2. If the number is negative, I should keep track of that and maybe reverse only the positive part first.
      3. After reversing, I need to change it back to a number and remove leading zeros. Like, 120 becomes 21, not 021. Super important!
      4. Now, before I return this number, I have to check if it fits in that 32-bit space.
      5. If it’s too big or too small, I just return 0. Sounds good!

      Here’s what my code could look like:

      function reverseInteger(num) {
    const INT_MAX = 2147483647;
    const INT_MIN = -2147483648;
    let sign = Math.sign(num);
    let reversed = parseInt(Math.abs(num).toString().split('').reverse().join('')) * sign;

    if (reversed > INT_MAX || reversed < INT_MIN) {
        return 0;
    }
    return reversed;
}

      So, like, if I test it with some numbers:

      • reverseInteger(123) should return 321.
      • reverseInteger(-456) should give me -654.
      • reverseInteger(120) should output 21!
      • And if I do reverseInteger(2147483647), it’s gonna return 0 because that’s too big after reversing.

      Aaand that’s my take on this whole reversing integers thing! Not super complicated, but I need to be careful with those limits!


    2. To tackle the challenge of reversing a 32-bit signed integer while adhering to its constraints, we would begin by converting the integer into a string for easy manipulation. The first step involves checking if the integer is negative. If it is, we can store this information and work with the absolute value for comfort. Once we have the absolute value, the next step is to reverse the string representation of that integer, then convert it back to an integer. Importantly, we strip away any leading zeros by converting it directly to an integer, which would automatically drop those zeros. This step ensures that numbers like 120 turn into 21 as intended.

      After reversing and cleaning the integer, the final step is to verify whether the reversed integer lies within the specified 32-bit signed integer range. If the result exceeds 2,147,483,647 or goes below -2,147,483,648, we return 0 to indicate an overflow condition. This check captures our edge cases effectively, particularly for inputs such as 1,000,000,000 or 2,147,483,647 where the results could stray outside valid bounds. This solution is efficient, handling leading zeros and verifying overflow in a streamlined manner, ensuring that all potential scenarios are accounted for.

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